SQL按拼音查詢
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GO
/****** 對(duì)象: UserDefinedFunction [dbo].[f_ch2py] 腳本日期: 01/27/2010 16:07:53 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
create function [dbo].[f_ch2py](@chn nchar(1))
returns char(1)
as
begin
declare @n int
declare @c char(1)
set @n = 63
select @n = @n +1,
@c = case chn when @chn then char(@n) else @c end
from(
select top 27 * from (
select chn =
'吖' union all select
'八' union all select
'嚓' union all select
'咑' union all select
'妸' union all select
'發(fā)' union all select
'旮' union all select
'鉿' union all select
'丌' union all select --because have no 'i'
'丌' union all select
'咔' union all select
'垃' union all select
'嘸' union all select
'拏' union all select
'噢' union all select
'妑' union all select
'七' union all select
'呥' union all select
'仨' union all select
'他' union all select
'屲' union all select --no 'u'
'屲' union all select --no 'v'
'屲' union all select
'夕' union all select
'丫' union all select
'帀' union all select @chn) as a
order by chn COLLATE Chinese_PRC_CI_AS
) as b
return(@c)
end
GO
/****** 對(duì)象: UserDefinedFunction [dbo].[F_GetHelpCode] 腳本日期: 01/27/2010 16:03:10 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[F_GetHelpCode] (
@cName VARCHAR(20) )
RETURNS VARCHAR(12)
AS
BEGIN
DECLARE @i SMALLINT, @L SMALLINT , @cHelpCode VARCHAR(12), @e VARCHAR(12), @iAscii SMALLINT
SELECT @i=1, @L=0 , @cHelpCode=''
while @L<=12 AND @i<=LEN(@cName) BEGIN
SELECT @e=LOWER(SUBSTRING(@cname,@i,1))
SELECT @iAscii=ASCII(@e)
IF @iAscii>=48 AND @iAscii <=57 OR @iAscii>=97 AND @iAscii <=122 or @iAscii=95
SELECT @cHelpCode=@cHelpCode +@e
ELSE
IF @iAscii>=176 AND @iAscii <=247
SELECT @cHelpCode=@cHelpCode + dbo.f_ch2py(@e)
ELSE SELECT @L=@L-1
SELECT @i=@i+1, @L=@L+1 END
RETURN @cHelpCode
END
使用：select * from Eforces_Incment where dbo.F_GetHelpCode(name) like ('Z%')